Math, asked by yamini74, 1 year ago

help me in this question

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Answered by Anonymous
1

Answer:

=Sec39°/ Cosec51° +2/√3 ×Tan38°×Tan60°×Tan52°×Tan73° -3(Sin^2 31° + Sin^2 59°)


=(Sec39/Sec39 )+

(2√3)×(Tan17°×Tan38°×Tan60×Cot38°×Cot17°) -3(Sin^2 31° +Cos^2 31°)


= 1 + 2/√3 ×Tan60° -3(1)


= 1+ ( 2/√3) ×√3 -1


= 1 +2 -1


=2

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