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On adding.eq.(i) and (ii);we get
=>(x+y) + (x-y)=5+5
=>2x =10
=>x =5
Putting x=5 in eq.(i) we get.
=>5-y=5
=>-y=0
=>y=0
=>(x+y) + (x-y)=5+5
=>2x =10
=>x =5
Putting x=5 in eq.(i) we get.
=>5-y=5
=>-y=0
=>y=0
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