Question

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The inner permineter or race track is 400m the length of each straight potion is 90m and. Both end are semi-circles find the cosr developing the race track at the rate rupee 12.50m2

Answer 1

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Let radius of the inner semi-circular ends = r m. 

Inner perimeter of the track = 400 m

 90 + πr + 90 + πr = 400 (Circumference of the semi-circle = πr)

2πr = 220 m

r = 35 m

 Area of the track = Area of the ring AEHD + Area of rectangle ABFE + Area of ring BFGC + Area of rectangle CDHG

= 3696 + 2520

= 6216 sq. m.

Length of the outer running track = EF + Length of arc FG + GH + Length is arc HE

= 90 + [π × (35 + 14)] + 90 + [ π × (35 + 14)]

= [2π × 49] + 180


= 308 + 180

= 488 m

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