Question

Help me

last .........xD​

Answer 1

Answer:

Given.,

X = 5-2root 6

Value of,

Root X = Root(5-2root6)

Baaki Yaar... Tu kar le...... xD

Answer 2

Given: $x = 5 - 2 \sqrt{6}$

To Find: $\sqrt{x}$

Solution:

$\sqrt{x} = \sqrt{5 - 2 \sqrt{6} } \\ \sqrt{x} = \sqrt{3 + 2 - 2 \sqrt{6} } \\ \sqrt{x} = \sqrt{ { \sqrt{3} }^{2} + { \sqrt{2} }^{2} - 2( \sqrt{3} )( \sqrt{2} ) }$

Using

$(x - y) ^{2} = {x}^{2} + {y}^{2} - 2xy$

$\sqrt{x} = \sqrt{( \sqrt{3} - \sqrt{2}) ^{2} } \\ \sqrt{x} = \sqrt{3} - \sqrt{2}$

Hope it Helps. ^_^