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An octagon has two equal angles each 120° and all the remaining six angles are equal. Find the measure of each of the six angles.
Angle sum of octagon will be =(n-2)x180=(8-2)x180=6x180 degree
as per given conditions two angles are 120 degree each and other six angles are equal . let six equal angle are X
six angle will be 6x
120+120+ 6 X =6x180
240+6X = 1080
6X=1080-240=840
X=840/6=140 degree
answer = 140 degree
Angle sum of octagon will be =(n-2)x180=(8-2)x180=6x180 degree
as per given conditions two angles are 120 degree each and other six angles are equal . let six equal angle are X
six angle will be 6x
120+120+ 6 X =6x180
240+6X = 1080
6X=1080-240=840
X=840/6=140 degree
answer = 140 degree
Anonymous:
sorry it should have been 4*180=720
pls wait for a while
i ll resend it
120+120+6p=720
so, 6p=720-240=480degree
so,p=480/6=80degrees
sorry actually, i was in a hurry so i typed it wrongly
really sorry
ans is not 140
it need to come out to be 80 degree
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Let all the remaining angle be x
Then
120+120+x+x+x+x+x+x = 360
240+6x = 360
6x = 120
X = 20 degree
If you satisfies mark this as brainliest
Then
120+120+x+x+x+x+x+x = 360
240+6x = 360
6x = 120
X = 20 degree
If you satisfies mark this as brainliest
ASP of an octagon is not 360 degree
Then??
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