Question

help me out in this.

what is sign of delta G for the process of ice melting at 283K​

Answer 1

Hey mate!

Here is your answer

Value of Δ G \Delta G ΔG is Gibbs free energy change. We know that melting point of ice is 273 K 273K 273K and boiling point is 283 K 283K 283K.

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Answer 2

Answer:

ΔG = 0

Expalination -

Melting of ice is spontaneous above 273K at 1 atm pressure

At 273K and 1 atm pressure, there is equilibrium

Hence, ΔG = 0