Question

help me out . question number 4and6 only

Answer 1

For question no. 4
[{(y)^3}^1/2]^1/3 + y^1/2

so by solving this we had
y^3*1/2*1/3

so we get
y^1/2 + y^1/2

= 2y^1/2


For question no. 4

we know that
area of triangle = 1/2 * base * height
let us assume that we are using equilateral triangle having each side "a"

so the height of the triangle is √(3)/2*side
= √(3)/2 *a

so area(ar1) is equal to
1/2 * a *√(3)/2
√(3)/4 *a sq. unit ......(1)


now the area(ar2) of new triangle will be

1/2 * 2a * √(3)/2 2a
√(3) a sq. unit. ......(2)

so, eqn (1) ÷ (2)
ar1/ar2 = [√(3)a/4] /√(3)a
ar1/ar2 = 1/4. (cancel √(3)a )
ar1 * 4 = ar2.

so the area of new triangle so formed is 4 times that of the initial one.