Question

help me out to get the answer ​

Answer 1

Step-by-step explanation:

consider the given quadratic equation:

6y²-7y+2=0

let a= 6 b=-7 c=2

the sum of the roots of the equation is

-b/a=7/6

the product of the roots of the equation is c/a= 2/6=1/3

we want new equation having roots 1/@ and 1/A and 1/B

the sum of the roots of the new equation is 1/A +1/B =(B+A)/BA

we know that A+B =-b/a

and AB=c/a

=>B+A/BA=(-b/a)/(c/a)

=>B+A/BA=-b/c=>>-(-7)/2=(7/2)

now

the product of the roots of new equation is.

1/A*1/B=1/AB=>1/c/a=a/c

1/A*1/B=6/2=>>3

now : the we have

y²-(sum of the roots)y+(product of the roots)=y2-(7/2)Y+3=0

2y2-7Y+6=0