Question

the volume occupied by 3.5g of NH3 at stp​

Answer 1

Answer: Volume occupied by 3.5 gm of NH3 at STP is 4.48 litre.

Explanation:

First we have to find no. Of moles

Molar mass of NH3 is 17. And the mass given in question is 3.5 gm.

No of moles = 3.5/17 =0.2 (approximately).

No of moles= Volume/22.4

No of moles * 22.4 = Volume

[No of moles = 0.2]

0.2 *22.4 = Volume

Volume = 4.48

Hope it helps.