Physics, asked by ITZAHILI, 1 day ago

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Answered by shreyas246
1

Object Distance(u) = 10 cm. (negative)

Focal length of the lens (f) = 5 cm.

We know, convex mirror always forms the virtual, upright and diminished.Also, Object distance in the convex mirror is always negative where as Image distance and focal length are positive.

Now, Applying the Mirror's Formula,

f

1

=

v

1

+

u

1

=

5

1

=

v

1

+

1

=

5

1

=

10v

(10−v)

10v=50−5v

15v=50

v=

3

10

so the image distance (v) =3.33cm.

Object Distance(u) = 10 cm. (negative)</p><p>Focal length of the lens (f) = 5 cm.</p><p></p><p>We know, convex mirror always forms the virtual, upright and diminished.Also, Object distance in the convex mirror is always negative where as Image distance and focal length are positive.</p><p></p><p>Now, Applying the Mirror's Formula,</p><p></p><p></p><p>f1 =v1 +u1</p><p></p><p></p><p>= 51 =v1 +1</p><p></p><p></p><p>=51 =10v(10−v)</p><p></p><p></p><p>10v=50−5v</p><p></p><p>15v=50</p><p></p><p></p><p>v=310</p><p></p><p></p><p>so the image distance (v) =3.33cm.</p><p></p><p>

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Answer By shreyas

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