help me outt................
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Hii its tom85
let y = sin^3x
diffrenciating with respect to x
dy/dx = 3sin^2xcosx
diffrenciattion of
sinx = cosx
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hope it may helps you
Answered by
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Answer:
Explanation:
sin^3x
(sinx)^3
put that value =y
therefore
y=(sinx)^3
let sinx=u
du/dx=cosx
y=u^3
dy/du=3u^2
multiply du/dx and dy/du
on multiplying we get
dy/dx
=3u^2cosx
=3sin^2cosx
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