Question

help me outt................​

Answer 1

Hii its tom85

let y = sin^3x

diffrenciating with respect to x

dy/dx = 3sin^2xcosx

diffrenciattion of

sinx = cosx

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hope it may helps you

Answer 2

Answer:

Explanation:

sin^3x

(sinx)^3

put that value =y

therefore

y=(sinx)^3

let sinx=u

du/dx=cosx

y=u^3

dy/du=3u^2

multiply du/dx and dy/du

on multiplying we get

dy/dx

=3u^2cosx

=3sin^2cosx