Math, asked by ayamakhoukhi8, 1 year ago

please how toprove that root (x square+1)-x>0

Answers

Answered by InvincibleBoy
8
Heya!!!

★Answer★

√(x^2+1)-x

=x + √1 - x

=1

as we know 1 > 0

hence, √(x^2+1)-x >0 [proved]
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