Question

Help Me Please I Am In Trouble?
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Answer 1

$\Huge{\textbf{Hey there!}}$

$\sf \ Given,\\\\\text{Magnitude of Electric Field (E)} = 10 \ N \ C^{-1}\\Height (d) =50 \ cm = 0.5 \ m\\Angle \ between \ E\ and \ d = 180^o~~~~~ [Straight \ line]$

$\sf We \ Know,\\V = E \cdotp d \ cos \theta \\V= -10 \times 0.5 \times cos \ 180^o~~~~~[vertically \ downward]\\V = -10 \times 0.5 \times -1 ~~~~~~~~~[\because cos \ 180^o = -1]\\\boxed{\boxed{\bf{V = 5 \ V}}}$

$\sf \textbf{Hence, electric potential as one goes up through 50 cm}\\\textbf{is 5 Volts.}$

$\Huge{\sf{\bf{Hope \ It\ Helps\ You!}}$