Question

help me please i need help​

Answer 1

Answer:

I think u are in 9 std.....

Answer 2

Step-by-step explanation:

Extend line AB such that it crosses line DE , mark the point as G. AB parallel to PF

Then BG parallel to CD( parts of parallel lines)

ED parallel to BC

GD parallel to BC(parts of parallel lines)

Therefore BCDG is a parallelogram (all opposite lines are parallel to each other)

Angle GBC = angle GDC( opposite angles of parallelogram)........1

Angle ABC + angle GBC= 180°

Angle GDC + angle FDE= 180° [Angles on the same line]........2

Angle ABC = Angle FDE( using 1 and 2)

Hence Proved