Help me please!
If the unit of length is tripled, the numerical value of area of square will be
(1) One ninth
(2) One sixth
(3) Nine times
(4) Remains same
Please answer the question with steps.
Answers
Answered by
117
Final Answer : 1/9
Let the unit of length be 1L.
Initial, value of 1L = k(say)
Then,
side of square be 'a'k units.
Area of square = ( a^2) k^2 units.
= a^2 L^2 units
Now,
Unit of length is tripled, 1L = 3k units.
=> 1k = L/3 .
Then,
Area of square is a^2 k^2 units.
=> a^2 (L/3)^2
=> a^2L^2/9 units.
There fore, Numerical value of area of square becomes 1/9 of initial in original units.
Let the unit of length be 1L.
Initial, value of 1L = k(say)
Then,
side of square be 'a'k units.
Area of square = ( a^2) k^2 units.
= a^2 L^2 units
Now,
Unit of length is tripled, 1L = 3k units.
=> 1k = L/3 .
Then,
Area of square is a^2 k^2 units.
=> a^2 (L/3)^2
=> a^2L^2/9 units.
There fore, Numerical value of area of square becomes 1/9 of initial in original units.
Cathenna:
Thank you so much!
Answered by
0
Answer:
one-nineth
Explanation:
3m=1 unit
m=1/3 unit
area= (m)^2
=(1/3)^2
area=1/9
Similar questions