Help me please!
In a closed room the temperature of a gas is 327 degrees Celsius, the pressure is 2 atm and the volume is 2 liters. If the gas temperature is raised to 527 degrees Celsius and the pressure becomes 1 atm, calculate the volume of the gas temperature.
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The sole other answer provided sounds quite practical. But it seems to me that this is a “Law of Ideal gasses” question. The evidence that makes me think so is the fact that the initial temp is 27 d C. Converting to Kelvin, the temp is 300 K. Since this is a multiple of 30 (factor of change of pressure); I am led to believe that this is indeed a Law of Gasses question.
Then: P (1) V (1)/T (1) = P (2) V (2)/T (2)
Plug in: (30) V / 300 = (1) (10 V)/ T (2)
Solve for T (2) → T (2) = 100 K (- 173 C)
If this was not the intent of the question, then the answer provided by PM satisfies.
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