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- Given :
➡ A set of 11 tuning fork is arranged in ascending order of freq. Each tuning fork given 5 beats per second with perceding one. The freq. of last fork is 1.5 times of that of first.
- To Find :
➡ Freq. of first and last fork
- Explanation :
➡ Each fork produced 5 beats per second with the previous means each fork has freq. 5Hz more than the previous.
➡ So the 11th fork will have freq. 10×5=50Hz more than the first.
➡ So this is an algebraic equation as
➡ 1.5x - x = 50
➡ x = 100
➡ frequency of first fork = 100 Hz
➡ frequency of 11th fork = 150 Hz (1.5 times of first fork)
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