Math, asked by llITZKITKAT07ll, 2 months ago

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Answered by Anushkas7040
3

Answer:

1)\\a^{2} +b^{2} +c^{2}+2(ab+bc+ac)

2)\\for\ facotirising-\\(a+b+c)(a^{2} -ab+b^{2} )\\\\ [for\ finding the value-]\\(a+b)^{3} -3ab(a+b)

3)\\8x^{3} +12x^{2}+6x+1

4)\\real

5)\\(a)^{2} +(b)^{2} =(c)^{2} \\

Step-by-step explanation:

1)

(a+b+c)^{2} =a^{2} +b^{2} +c^{2}+2ab+2bc+2ac\\\ \ \ \ \ \ \ \/ \ \ \ \ \ \ \ \ \ \ \ \ => a^{2} +b^{2} +c^{2}+2(ab+bc+ac)

2)

for\ facotirising-\\(a+b+c)(a^{2} -ab+b^{2} )\\\\ [for\ finding the value-]\\(a+b)^{3} -3ab(a+b)

3)

(2x+1)^{3} \\=>(2x)^{3}+(1)^{3}  +(3)(2x)(1)(2x+1)\\=>8x^{3} +1+6x(2x+1)\\=>8x^{3} +1+12x^{2} +6x\\=>8x^{3} +12x^{2}+6x+1

Using identity-

(a+b)^{3}=a^{3} +b^{3}+ 3ab(a+b)

4)

Every rational number is a real number.

5)

(a)^{2} +(b)^{2} =(c)^{2} \\

Where

a = base of right-angled triangle

b=Perpendicular of right-angled trianlge

c=Hypotenuse of right-angled trianlge

Answered by smritikanamaity
2

Answer:

1. a×a+b×b+c×c

2. a×a×a+b×b×b

3. 2x×2x×2x=8x+1

4. real number

5. see the attachment

Step-by-step explanation:

hope it's helpful

please mark me down as brainleast

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