Math, asked by Dove23, 1 year ago

HELP me PLEASE
thankyou

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Answers

Answered by smartboyGanesh
1

Answer:


LHS = (CotA -1) /( 2- Sec²A )


= ( CotA-1) / (1 + 1 - Sec²A)


= (1/tanA)-1 / ( 1 - tan²A) ●Since tan²A +1 = sec²A So, 1- Sec²A = - tan²A


= (1-tanA) / tanA (1+tanA)(1-tanA) ● by identity a² -b² = (a+b) ( a-b)


= 1/ tanA(1+tanA)


= CotA / (1+tanA) = RHS


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