help me please to find the answer.....
Attachments:
Answers
Answered by
1
Answer: please find the attached file.
Step-by-step explanation:
Attachments:
adityaaryaas:
Welcome Kriti (^_^)
Answered by
0
sinA/cosA+cosA/sinA
:sin (90-A) =cosA ,cos(90-A) =sinA
sin sq A+cos sq A/sinAcosA
1/sinAcosA. (sin sq A+cos sq A=1)
secAcosecA. (1/sinA=cosecA,1/cosA=secA)
Similar questions