Help me please
what is the discriminant?
number of solutions?
quadratic formula?
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hey..
x^2 + 2x - 8 = 0
a = 1 b = 2 c = -8
b^2 - 4ac = (2)^2 - 4(1)(-8) = 4 + 32 = 36
b^2 - 4ac > 0 so two real zeroes
quadratic formula and the rest answer is in attachment check it
x^2 + 2x - 8 = 0
a = 1 b = 2 c = -8
b^2 - 4ac = (2)^2 - 4(1)(-8) = 4 + 32 = 36
b^2 - 4ac > 0 so two real zeroes
quadratic formula and the rest answer is in attachment check it
Attachments:
Answered by
0
hope it will help uh ...
nd plz mark as brainliest ...
nd plz mark as brainliest ...
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