Physics, asked by nishantmehta12057, 9 months ago

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Answered by Madalasa22
1

L = 10000m 

D = 2mm r = D/2 = 1 × 10^(-3)m P = 2.7 × 10^(-8)ohm m 

R =  ? 

we know that ,  

R = pL/A 

A = πr² 

A = 22/7 × 1 × 10^[(-3)]² 

R = 2.7 × 10^(-8) × 1000 × 1[ 22/7 × 1 × 10^[(-3)]² ] 

R = 85.9 ohm ≈ 86 ohm

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Answered by Anonymous
4

Answer:

l = 10000m \\ d = 2mm \: r = d |2 = 1 \times  10( - 3)m \: p = 2.7 \times  \: 10 \: ( - 8) \: ohm \: m \\  =  >   {r}^{?}  \\ we \: know \: that  \\ r = pl | \: a \\ a = \pi   {r}^{2}  \:  \\ a = 22 | \: 7 \times 1 \times 10  |( - 3 )|  ^{2}  \: \\  r = 2.7 \times 10( - 8) \times 1000 \times 1(22 |7 \times 1 10 |( - 3)|  ^{2} \\ r = 85.9 \: ohm \:  = 86 \: ohm

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