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A current of 0.5 A passes through a conductor in 2 second. How many electrons flow through this conductor from one end to the other end during this interval of time? Charge on each electron is 1.6 ×10^-19C
Answer is 6.25 ×10^18 electrons
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we have I=q/ t
so I*t=q
so 0.5*2=q=1
now
q=no. of e*charge of one e
hence 1=(1.6*10^-19)*no. of e
so no. of e=6.25*10^18
so I*t=q
so 0.5*2=q=1
now
q=no. of e*charge of one e
hence 1=(1.6*10^-19)*no. of e
so no. of e=6.25*10^18
aanchanpandey:
Aap ne sirf answer write kar diya hai solve to kiya hi mai to may kase samjo
But thanks
sorry! but I need points to ask question.
because of this I m giving nonsense answer
Ok
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