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Explanation:
let theta = t
x = 5 + (6*cosec(t))
y = 3 + (8*cot(t))
Thus, cosec(t) = (x-5)/6
.... cot(t) = (y-3)/8
Now as (cosec(t))^2 - (cot(t))^2 = 1
Thus
((x-5)/6)^2 - ((y-3)/8)^2 = 1
Hence theta is eliminated
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here is your answer ........
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