Math, asked by kumartanishq2040, 9 months ago

Q 47.

The sum of three consecutive numbers is 99. The middle one is ​

Answers

Answered by abhishekbansal3110
1

Answer:

let the no. = x,x+1,x+2

x+x+1+x+2=99

3x+3=99

3x=99-3

3x=96

x=96/3

x=32

x+1=32+1=33

x+2=32+2=34

middle one no. is 33

Answered by hardik13968
0

Answer:

33

Step-by-step explanation:

Let 3 consecutive nos. be (a-d), (a). (a+d)

Then their sum is 99(A.T.Q)

a-d+a+a+d=99

3a=99

a=33

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