help me plz plz plz plz plz plz plz plz
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Answered by
2
Hello.... ☺
please refer to the attachment above
thank you
please refer to the attachment above
thank you
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jaya1012:
Ans is incomplete
u have to find partial pressure. .
Answered by
0
Hey mate....
here's Ur answer....
Given ......
Moles of dioxygen - 70.6g/ 32g mol^-1
= 2.21 mole
Mole fraction of dioxygen - 2.21/10.585
= 0.21
Moles of Neon = 167.5 / 20 g mol^-1
= 8.375 mole
Mole fraction of Neon = 8.375/10.585
= 0.79
Hope it Helps❤
here's Ur answer....
Given ......
Moles of dioxygen - 70.6g/ 32g mol^-1
= 2.21 mole
Mole fraction of dioxygen - 2.21/10.585
= 0.21
Moles of Neon = 167.5 / 20 g mol^-1
= 8.375 mole
Mole fraction of Neon = 8.375/10.585
= 0.79
Hope it Helps❤
Didn't find the partial pressures. ...
u copied top
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