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Question number 15
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Step-by-step explanation:
y = √(p + 2q) + √(p - 2q) / √(p + 2q) - √(p - 2q)
//multiply numerator and denominator with √(p + 2q) + √(p - 2q)
y = [√(p + 2q) + √(p - 2q)]² / p + 2q - p +2q
y = p + 2q + p -2q - 2√p² - 4q² / 4q
y = p - √p² - 4q²/2q.
qy² - py + q = 0
q[p - √p² - 4q²/2q]² - p [p - √p² - 4q²/2q] + q
= q[p²+ p²- 4q² - 2p√p² - 4q²]/4q² - [ p²- p√p² - 4q²/2q] + q
= [p²+p²- 4q² - 2p√p² - 4q²]/4q - [ p² - p√p² - 4q²/2q] + q
=> 2p² - 4q² - 2p√p² - 4q² - 2p²+ 2p√p² - 4q² + 4q²
=> 0
Hence proved.
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