Question

Help me solve this question..​

Answer 1

Answer:

x=2

Step-by-step explanation:

$2^{3x-1} +10=6*7\\2^{3x-1} =42-10\\2^{3x-1} =32\\2^{3x-1} =2^{5}$

⇒$3x-1=5\\ 3x=5+1\\3x=6\\x=2$

Answer 2

Answer:

x=2

Step-by-step explanation:

\begin{lgathered}2^{3x-1} +10=6*7\\2^{3x-1} =42-10\\2^{3x-1} =32\\2^{3x-1} =2^{5} \\\end{lgathered}

2

3x−1

+10=6∗7

2

3x−1

=42−10

2

3x−1

=32

2

3x−1

=2

5

⇒\begin{lgathered}3x-1=5\\ 3x=5+1\\3x=6\\x=2\end{lgathered}

3x−1=5

3x=5+1

3x=6

x=2