Help me solving the forth question please....
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Anonymous:
i wont help f***
Please try
wont try what can u do?
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Answered by
4
Heya mate, Here is ur answer
In ∆ One,
Base = 24 m ( diagonal will become base)
Height=13 m
Area of ∆ one = 1/2×base ×height
=1/2×24×13
=12×13
=156 m^2
In ∆ 2
Base =24 m
Height=8 m
Area of ∆ 2 =1/2 ×base × height
=1/2 × 24×8
= 12×8
=96 m^2
Area of quadrilateral=Area of ∆ 1 + Area of ∆2
= 156+96
=252 m^2
===============================
Warm regards
@Laughterqueen
Be Brainly ✌✌✌
In ∆ One,
Base = 24 m ( diagonal will become base)
Height=13 m
Area of ∆ one = 1/2×base ×height
=1/2×24×13
=12×13
=156 m^2
In ∆ 2
Base =24 m
Height=8 m
Area of ∆ 2 =1/2 ×base × height
=1/2 × 24×8
= 12×8
=96 m^2
Area of quadrilateral=Area of ∆ 1 + Area of ∆2
= 156+96
=252 m^2
===============================
Warm regards
@Laughterqueen
Be Brainly ✌✌✌
Thank you very much
Hi
What's your name
mah pleasure ☺ and no chats pls
Ok
Answered by
2
Heya mate, Here is ur answer
In ∆ One,
Base = 24 m ( diagonal will become base)
Height=13 m
Area of ∆ one = 1/2×base ×height
=1/2×24×13
=12×13
=156 m^2
In ∆ 2
Base =24 m
Height=8 m
Area of ∆ 2 =1/2 ×base × height
=1/2 × 24×8
= 12×8
=96 m^2
Area of quadrilateral=Area of ∆ 1 + Area of ∆2
= 156+96
=252 m^2
===============================
Warm regards
@Unknown
Be Brainly ✌✌✌
Read more on Brainly.in - https://brainly.in/question/6853240#readmore
Laughter queen ka
Ok
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