Question

help me to figure out this one.

Answer 1

Heya......!!!!


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** In this question the acceleration which is asked is " Total Acceleration " ,, so we will apply the formulae of total acceleration .

=> Total acceleration is the vector sum of centripetal acceleration and tangential acceleration .

$we \: know \: that \: \frac{dx}{dt} = \: v \\ = > \: \frac{dx}{dt} = 2t \\ = > putting \: the \: value \: of \: t \: \: we \: get \: \\ = > \: 2t \: = 2 \times 1 = 2 \: \frac{m}{sec} \\ \\ centripetal \: acceleration \: = \: \frac{v {}^{2} }{r} \\ = > \: \frac{4}{2} = 2 \frac{m}{sec {}^{2} } \\ \\ tangential \: acceleration \: = \: \frac{dv}{dt} \\ = > \: \frac{d(2 )}{d(1)} \: = \: 2 \frac{m}{sec {}^{2} } \\ \\ total \: acceleration \: = > \sqrt{2 {}^{2} + 2 {}^{2} } \\ = > \sqrt{4 + 4} \\ = > \sqrt{8} \\ = > 2 \sqrt{2} \: \: \frac{m}{s {}^{2} }$


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Answer 2

Answer:

in this question the acceleration which is asked is " Total Acceleration " ,, so we will apply the formulae of total acceleration .

=> Total acceleration is the vector sum of centripetal acceleration and tangential acceleration .

=v

=>

dt

dx

=2t

=>puttingthevalueoftweget

=>2t=2×1=2

sec

m

centripetalacceleration=

r

v

2

=>

2

4

=2

sec

2

m

tangentialacceleration=

dt

dv

=>

d(1)

d(2)

=2

sec

2

m

totalacceleration=>

2

2

+2

2

=>

4+4

=>

8

=>2

2

s

2

m

hope it helps please mark me