Question

help me to solve these all question plz​ I will mark him as brilliant who give the correct answer with step by step explanation ​

Answer 1

(4) Sinθ × Cosθ

Let, θ = 90°

Now, Sin 90° × Cos 90° = 1 × 0 = 0

So, The option is (d) 0.

(5) Tan θ = (c) $\frac{1}{cotθ}$

(6) In a ️ABC right angled at C then Sinθ is

If, Sinθ = $\frac{perpedicular}{hypotenuse}$

So, (d) AB/ CA.

(7) In a ️ABC right angled at C then Cosθ is

If, Cosθ = $\frac{base}{hypotenuse}$

So, BC/AC or AC/BC.