Question

help me to solve this

Answer 1

hey
here's your answer!!

let the two numbers be x and y.
ATQ,
x/y = 1/2
=> x = 2y
=> x- 2y = 0. ..........(1)

Now the new ratio is,
x-5/y+4 = 5/4
=> 4(x-5) = 5(y+4)
=> 4x -20 = 5y + 20
=> 4x -5y = 40 .......... (2)

Multiplying (1) with 4....
We get, 4x - 8y = 0

Solving (1) and (2)....

4x - 8y = 0
4x -5y = 40

we get,
3y = 40
:. y = 40/3
:. x = 80/3.

Hope it helps!!

Answer 2

Let number = x/y = 1/2 => y=2x

Given,

x-5/y+4 = 5/4

=> 4x-20 = 5y+20
=> 4x-20 = 5(2x)+20
=> 4x-20 = 10x+20
=> -6x = 40
=> x = -40/6 = -20/3
y = 2(-20/3) = -40/3

Hope u understand pls mark it as brainliest....