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We know E = h ν
h = 6.626 x 10⁻³⁴ J Hz⁻¹
given ν₀ = 7.0 x 10¹⁴ s⁻¹ ; ν = 1.0 x 10¹⁵ s⁻¹ .
total energy provided = (threshold enegry) + (kinetic energy)
⇒ hν = hν₀ + KE
⇒ h x 1.0 x 10¹⁵ s⁻¹ = h x 7.0 x 10¹⁴ s⁻¹ + KE
⇒ h x ( 1.0 x 10¹⁵ s⁻¹ - 7.0 x 10¹⁴ s⁻¹ ) = KE
⇒ 6.626 x 10⁻³⁴ J Hz⁻¹ x 3 x 10¹⁴ Hz = KE
⇒ KE = 1.9878 x 10⁻¹⁹ J
Hope this helps you ✌️✌️☘️☘️.
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Answer:
Given that,
vo=7.0×1014s−1
v=1.0×1015s−1
As we know, hv=hv0+21mv2
i.e. h(v−v0)=K.E.
∴K.E.=(6.626×10−34)×(1.0×1015−7.0×1014)=6.626×10−34×1014(10−7)
∴K.E=19.878×10−20J
Explanation:
please pinky iam sorry
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