Help me to solve this 2nd q. Plz
Attachments:
Answers
Answered by
1
Hey friend..... this will help you........ nd Good morning too
-MRS. JUNGKOOK
-MRS. JUNGKOOK
Attachments:
nitinsoniboss26:
Good morning friend & thnx yr
Answered by
3
hey mate,
here is your answer...
p(x)=2x^2+5x-12=0
p(-4)=(2×-4^2)+(5×-4)-12=0
=32-20-12=0
=12-12=0
hence,
p(-4)=0
hope it will help you....
here is your answer...
p(x)=2x^2+5x-12=0
p(-4)=(2×-4^2)+(5×-4)-12=0
=32-20-12=0
=12-12=0
hence,
p(-4)=0
hope it will help you....
But here p(-4) is present
i have correct it its my mistake sry.
Similar questions