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Step-by-step explanation:
in this AE=BE Because chord Subtended at the centre bisects the chord
in aec and bec
AE=BE
<AEC=<BEC (90°)
CE = CE (common)
∆AEC≈∆BEC
BY CPCT
AC=BC
Therefore ∆ABC IS ISOSCELES CUZ BOTH SIDES EQUAL
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refer to the attachment sis
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