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(iii) y+70°=180°
y=180-70=110°
x=180-(30+110)=180-140=40°
y=180-70=110°
x=180-(30+110)=180-140=40°
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1) find angle y by linear pair
130+y=180
y=50
and find x by triangle angle sum property
x+y+70=180
x=60°
2)find y from triangle angle sum property then for x first find angle CDB and then apply triangle angle sum property on ∆CBD
3as an exterior angle is the sum of opposite interior angles find x by subtracting 30 from 70 and then apply triangle angle sum property
130+y=180
y=50
and find x by triangle angle sum property
x+y+70=180
x=60°
2)find y from triangle angle sum property then for x first find angle CDB and then apply triangle angle sum property on ∆CBD
3as an exterior angle is the sum of opposite interior angles find x by subtracting 30 from 70 and then apply triangle angle sum property
Natalie11:
equate this
2nd and 3rd
2) 85+50+ y =180. ... y =45°
135-180=x (angle sum). ... x=45°
70=30+x ...x=40°
by angle sum
x+y+30=180. ... y = 110°
ok
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