Help me with this question please.
Attachments:
Answers
Answered by
0
u should find 0 of the poly
iamavery:
even I know that
Answered by
0
Let the polynomial be p(x) = ax²+bx+c
Given , sum of zeroes= 6/1 = -(-6)/1 = -b/a
Product of zeroes= 9/1 = c/a
:. a=1 , b= -6 , c= 9
Hence , the quadratic polynomial p(x) = x²-6x+9
Given , sum of zeroes= 6/1 = -(-6)/1 = -b/a
Product of zeroes= 9/1 = c/a
:. a=1 , b= -6 , c= 9
Hence , the quadratic polynomial p(x) = x²-6x+9
Similar questions