HELP MEE lcm of this x^3+x^2+x+1 and x^3-x^2+x-1
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x^3+x^2+x+1.
=x^2(x+1)+(x+1)..
= (x+1)(x^2+1)..
x^3-x^2+x-1.
x^2(x-1)+(x-1).
=(x-1)(x^2+1)
lcm=(x+1)(x-1)(x^2+1)
=(x^2-1^2)(x^2+1)
lcm=x^4-1..
=x^2(x+1)+(x+1)..
= (x+1)(x^2+1)..
x^3-x^2+x-1.
x^2(x-1)+(x-1).
=(x-1)(x^2+1)
lcm=(x+1)(x-1)(x^2+1)
=(x^2-1^2)(x^2+1)
lcm=x^4-1..
VaibhavSharma1:
Got it bro
:)
naman can we take out the roots and then multiply them... if not then why??
no...dear... u have to answer only in terms of variables.....and remember you have to find factors not to evaluate it.....which means only variables
finding roots ...means evaluation....
yess bhaii Thankss alottt brother. thanks from kota!
wlcm... :)
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