Question

help meeeeee please so bad

Answer 1

$\rm{\:1 \:mole\:KClO_3\:mass = 39+35.5+3(16) = 122.5g}$

$\rm{\:2.5\:mole\:KClO_3\:mass = 2.5\times 122.5 = \bf{\red{306.25g}}}$