Chemistry, asked by laylahaney, 5 months ago

help meeeeee please so bad

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Answered by tarracharan

$\rm{\:1 \:mole\:KClO_3\:mass = 39+35.5+3(16) = 122.5g}$

$\rm{\:2.5\:mole\:KClO_3\:mass = 2.5\times 122.5 = \bf{\red{306.25g}}}$

laylahaney: its right

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