Question

Help... My math teacher didn't teach us how to do this

Answer 1

Solution :

Both figures are Trepeziums.

/* Area of a trapezium (A)

= (1/2) [ (sum of parallel sides )× height ] */

i ) Area of first trapezium (A1)

= (1/2){ [ (x+4)+(2x-6)]×6 ]

= (3x-2)3

= 9x -6 ----(1)

ii ) Area of the second trapezium (A2) = (1/2)[(x+x+2)4]

= (2x+2)2

= 4x+4 -----(2)

According to the problem given,

(1) = (2)

=> 9x-6 = 4x+4

=> 9x-4x = 4+6

=> 5x = 10

=> x = 10/5

=> x = 2

Therefore,

x = 2

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