Computer Science, asked by SohamKundu012, 1 year ago

Help needed

Please write a program to check whether a number is special number or not .

100 points ​

Answers

Answered by Anonymous
9

\underline{\mathbb{CODE}}

import java.util.*;

class special_number

{

public void main()

{

Scanner sc=new Scanner(System.in);

System.out.println("Enter a number to check whether it is special number or not");

int n=sc.nextInt();

int d=0;

int cpy=n;

int s=0;

while(n>0)

{

d=n%10;

int f=1;

for(int i=1;i<=d;i++)

{

f=f*i;

}

s=s+f;

n=n/10;

}

if(s==cpy)

{

System.out.println("Special number");

}

else

{

System.out.println("Not a special number");

}

}

}

   

\textbf{\underline{Explanation}}

→ The special number is a number whose sum of factorial of each digit is equal to the number .

→ We will use digit extraction to extract the digits .

→ Then inside the while-loop we run another loop for calculating the factorial .

→ We will add the factorial .

→ Then we will check whether the sum is equal to the number or not .

→ If it is equal , print that the number is special otherwise it is not special .

→ A copy variable is required in the coding .


SohamKundu012: tysm for help
Answered by Anonymous
1

\huge\red{Answer }

import java.util.*;

class special

{

public static void main(String args[])

{

Scanner sc=new Scanner(System.in);

int n,i,d,sum=0,fact=0;

System.out.print(“Enter an integer:”);

n=sc.nextInt();

i=n;

while(i>0)

{

d=i%10;

i/=10;

for(int a=1;a<=d;a++)

{

fact*=a;

}

sum+=fact;

fact=0

}

if(sum==n)

System.out.println(“Special Number”);

else

System.out.println(“Not a Special

Number”);

}

HOPE IT HELPS YOU !!

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