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Physics class 9.
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Answers
this is a second answer
answer 1.= v=36 km/hr
v=36×
18
5
=10 m/s
u=0
t=10 sec
v=u+at
10=0+a(10)
10=10a
a=1 m/s
2
answer 3= a = 1 m/s². Hence, the acceleration of the car is 1 m/s². ⇒ s = 37.5 m. Hence, the distance covered by car is 37.5 m.
answer 4 =u=108km/h=
60×60
108×1000
=30m/s
a=−1m/s
2
v=0m/s
From 3rd equation of motion,
2as=v
2
−u
2
−2×1×s=0
2
−30×30
s=
−2×1
−30×30
s=450m
answer 5 = 40km/h = 11.11m/s, 58km/h = 16.11m/s
Let’s review the 4 basic kinematic equations of motion for constant acceleration (this is a lesson – suggest you commit these to memory):
s = ut + ½ at^2 …. (1)
v^2 = u^2 + 2as …. (2)
v = u + at …. (3)
s = (u + v)t/2 …. (4)
where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time.
In this case, we have v1 = u + at = 11.11 , v2 = u + a(t+1) = 16.11
So at = 11.11 – u …. (1)
a(t+1) = at + a = 16.11 – u …. (2)
sub (1) in (2)
11.11 – u + a = 16.11 – u
a = 16.11 – 11.11 = 5.0
The acceleration is 5.0m/s^2
all are correct answer
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