Help please!!
(1/a+b+x)=(1/a)+(1/b)+(1/x)
How to resolve it?
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Answer:
1/(a+b+x) = 1/a + 1/b + 1/x
=> 1/(a+b+x) - 1/x = 1/a + 1/b
Take the LCM
=> (x - a - b - x)/x(a+b+x) = (a+b)/ab
=> -(a+b)/x(a+b+x) = (a+b)/ab
(a+b) is common on the both the sides, cancel it
=> -1/x(a+b+x) = 1/ab
=> - ab = ax + bx + x^2
=> x^2 + ax + bx + ab = 0
=> x(x + a) + b(x + a) = 0
=> (x + b)(x + a) = 0
=> x = (-b),(-a)
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