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Sinx/x limit as x approaches 0 shall become lim cosx/x as x approaches 0. Again checking the value in expression, cos0=1 and x=1, 1/1=1. Therefore, this limit works out to 1. Similarly, tanx/x limit as x approaches 0 is also 1.
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Sinx^0 is constant function (x not equal to 0)and is equal to sin1, so value of limit is also sin1, irrespective of the number to which x approaches. If the limit of a function exists for a particular value of x, the limit when x is approached from the left side of 0 must be equal to the limit when x is approached from the right side of /. The limit doesn't actually exist, since the the this isn't the case here.
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