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Answer:
The solution is given in the above image
Note Your question is wrong in the denominator I have replaced 3 by 2
Step-by-step explanation:
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Let √(x)/(x - 3) = t , so, √(x - 3)/x = 1/t
Therefore,
=> t + 1/t = 5/3
=> (t² + 1)/t = 5/3
=> 3(t² + 1) = 5t
=> 3t² - 5t + 3 = 0
Notice that the discriminant of this equation is (-5)^2 - 4(3)(3) = - 11 < 0 , it means it has no real solution and no real value of t satisfies this.
Moreover, in complex numbers:
t = (-(-5) ± √-11)/3(2) = (5 ± √11i)/6
Hence,
x/(x - 3) = t² = ((5 ± √11i)/6)²
x/(x - 3) = (7 ± 5√11i)/18
18x = (x - 3)(7 ± 5√11i)
18x = 7x ± 5xi√11 - 21 ± 15i√11
11x ± 5xi√11 = ± 15i√11 - 21
x(11 ± 5√11i) = (±15i√11 - 21)
x = (±15i√11 - 21)/(11 ± 5√11i)
You can solve this further, rationalize the denominator. On solving,
x = (3/2) ± (15√11i)/22