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Pb plus HNO3 = Pb(No3)2 plus No2 plus H2O.
Set the coefficiebts and calculate the lead mass needed to form 2L NO and volume of solution 0.1M HNO3
Answers
Explanation:
Lead(II) nitrate can be obtained by reaction of lead(II) oxide with nitric acid[9]
PbO + 2 HNO3 → Pb(NO3)2 + H2O
When concentrated nitric acid is used, crystals of lead nitrate are obtained as the common ion effect reduces the solubility of lead nitrate in this medium.[10]
The compound crystallizes in the face-centred cubic system, space group Pa3Z=4 (Bravais lattice notation), with unit cell length 784 pm.[11] There is no evidence for free internal rotation of the nitrate groups within the crystal lattice at elevated temperatures.
In nitric acid treatment of lead-containing wastes, e.g., in the processing of lead–bismuth wastes from lead refineries, impure solutions of lead(II) nitrate are formed as by-product. These solutions are reported to be used in the gold cyanidation process.[12]
When concentrated sodium hydroxide solution is added to a nitrate solution, basic nitrates may be formed. Up through the half equivalence point, Pb(NO3)2·Pb(OH)2 predominates, then after this point Pb(NO3)2·5Pb(OH)2 is formed. Simple Pb(OH)2 is not formed up to at least pH 12.[13][14]
Lead(II) has a standard reduction potential (E0) of −0.125 V and the nitrate ion has an E0 of +0.956 V.[15] These properties show that lead(II) nitrate can behave as an oxidizing agent only towards easily oxidized substrates.
When heated, lead(II) nitrate crystals decompose to lead(II) oxide, oxygen and nitrogen dioxide.
2 Pb(NO3)2 (s) → 2 PbO (s) + 4 NO2 (g) + O2 (g)
Because of this property, lead nitrate is sometimes used in fireworks.[