Math, asked by skakifilahi, 5 hours ago

help please.
thank you.​

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Answered by NITESH761
0

Step-by-step explanation:

We have,

\rm x^2+x-6=0

\rm x^2+3x-2x-6=0

\rm x(x+3)-2(x+3)=0

\rm (x-2)(x+3)=0

\rm x=2\:or\:x=-3

Answered by PritishKantiDatta
1

Please mark me as brainliest and hope it helps

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