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Answers
Answer:
To find the length of PM
Triangle OMP is a right angled triangle
Therefore by using Pythagoras theorem
(Hypotenuse)² = (base)² + (height)²
5² = 4² + PM²
25 = 16 + PM²
25 - 16 = PM²
9 = PM²
√9 = PM
3 = PM
Therefore, Length of PM is 3cm.
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HOPE IT HELPS YOU!
Heya mate... here you go...
In the given figure ∠LOP = ∠MOP , OL = 4cm , OP = 5cm , ∠PLO = ∠PMO [ as right angles ]
Firstly we have to prove that traingle LOP is congruent to traingle mop
se we will proof the congruence of those traingle
s
In traingle LOP and traingle MOP
∠LOP = ∠MOP
OP = OP [common]
∠PLO = ∠PMO [ right angles ]
Hence , ΔLOP ≅ΔMOP
PM = PL [ by CPCT ]
So , here we have got to know that PL = PM so if we find tHe value of PL it will be equal to PM
So , we can find the value of PL by the pythagoras theorem that is to be applied in ΔPLO ,
OP²= LP²+OL²
[5]²= [4]²+LP²
25= 16 +LP²
LP²= 25- 16
LP= √9 = 3cm
As we know that PM= PL
So , PL = PM = 3cm
have a good day ahead friend...