Question

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Answer 1

the answer is 8j

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Answer 2

Heat absorbed from A to B

Here pressure is constant

So W = p (∆V) = 10( 400-200)/1000 = 2000/1000 = 2 J as volume in cc

So 10× 1000/ (400-200)10^6 = 2J

As W is zero For B- C

Lets calculate Internal energy change from A- C

As ∆U from A- B- C- A that is when it comes back to A is 0

(∆U) A- c + ∆U c-A = 0

Also Internal energy do not depend on path so from A- B- C

or A- C it will be same

Q = ∆U + 2

Q = 8

∆U = 8-2 = 6

Now From A to C

Lets find eq of PV

Slope = (20-10)/ 400-200 = 10/200 = 1/20

p -20 = 1/20 ( V- 400)

20 P - 400 = V-400

20 P = V

p= V/20

W = integration of P dv

= integration of V dv/20 ( limits 200-400)

= V ^2/40 ) limits 200-400

= 4000 -1000 = 3000

So w = 3000/1000 = 3J

Q = ∆U +W = 6 +3 = 9 J

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