help pls physics doubt
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2
Answer:
F=A cosBx+C sinDt
the argument, θ of cos or sin should be dimensionless.
therefore,
dimension of Bx =[MLT]
[B][L ′ ]=[MLT]
[B]=[ML0T]
Similarly [D][T ′ ]=[MLT]
[D]=[MLT 0
dimension of DB=
[ML 0 T] [MLT 0 ]
[L 1 T −1 ]
Answered by
1
Answer:
Answer:
F=A cosBx+C sinDt
the argument, θ of cos or sin should be dimensionless.
therefore,
dimension of Bx =[MLT]
[B][L ′ ]=[MLT]
[B]=[ML0T]
Similarly [D][T ′ ]=[MLT]
[D]=[MLT 0
dimension of DB=
[ML 0 T] [MLT 0 ]
[L 1 T −1 ]
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